Question

the number of real roots of the equation , (x-1)^2 + (x-2)^2 + (x-3)^2 +(x-4)^2 + ... +(x-n)^2 = 0 , (n>1) is :​

Answer 1

Answer:

0

Step-by-step explanation:

(x−1)2+(x−2)

2+(x−n)2=0

clearly this is a quadratic equation equation equation since all the terms are quadratic.

Now, we know square of any term is always non-negative .

Answer 2

Answer:

Answer:- 0

Step-by-step explanation:

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