Math, asked by singhrajeev1974, 8 months ago

The number of real roots of the equation (x+3)²+(x+1)²+(x-5)²+(x-6)²=0 is

Answers

Answered by sujavelayutham
0

Step-by-step explanation:

Sal solves the equation (x+3)²-4=0 and finds the x-intercepts of f(x)=(x-2)²-9. ... x+ 3^2 to be 2x+9=4 -subtract by 9 which would be 2x=-5 that wont work either. Reply. Reply to ... 1) You can solve using square root method, as shown in the video. 2) You can ... Factor the trinomial: find factors of 4 that also add to 6. Use 5 and 1.

If it helps please make me as brainliest. Thank you

Answered by parthsingh8160
0

Answer:

hypjh

dnfjgi

dmrirk

dkriro Buchanan

horrific

Bobbi

hockey

high

home. GL. GL

Dirk

Goog

Similar questions