Question

the number of real roots of (x+1/x)3+(x+1/x)=0 is​

Answer 1

Answer:

Step-by-step explanation:

Given y^3 + y = 0

=> y×(y^2 +1) = 0

=> y^2 +1 = 0

=> y = + i or -i

x + 1/x = 0

=> x^2 + 1 = x × 0 = 0

=> x = +i or -i.

So for a real x , x+1/x is not 0.

hope it helps you

Answer 2

Answer :

the number of real roots of (x+1/x)3+(x+1/x)=0