the number of real solutions of the equation tan^-√x(x+1)+sin^-√x2+x+1=π/3 is
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Step-by-step explanation:
Tan-1 [x2+x]1/2 + sin-1 [x2+x+1]1/2 = pi/2
= tan-1[x2+x]1/2 + sin-1 [x2+x+1]1/2 = sin-1 [x2+x+1]1/2 + cos-1 [x2+x+1]1/2
= tan-1 [x2+x]1/2 = cos-1 [x2+x+1]1/2
= cos-1[1/ (x2+x+1)1/2] = cos-1[x2+x+1]1/2
= 1/ (x2+x+1)1/2 = [ x2+x+1]1/2
= x2+x+1 = 1
= x2+x = 0
=x(x+1) => x=0 or x = -1
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