Question

The number of revolution made by an electron in the second bohr orbit of Li+2 in 1 hour is​

Answer 1

.If r

2

is the radius of second Bohr orbit, the distance traveled by an electron is 2πr2

Revolutions per sec =

2πr2

v2

R2 =2

2 ×r

1

=4×0.53×10

−8

=2.12×10

−8

cm

∴ Number of revolution =

2×3.14×2.12×10

−8

1.09×10

8

=8.18×10

14

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