Physics, asked by nesanurugeethika2004, 8 months ago


The number of revolutions done by an
electron 'e' in one second in the first orbit of
hydrogen atom is
1) 6.57x10' 2) 6,57 x 10" 3) 1000 4) 6.57 x 10'
10-10​

Answers

Answered by nishameenapura
0

Explanation:

Revolutions per sec =

2πr

2

v

2

r

2

=2

2

×r

1

=4×0.53×10

−8

=2.12×10

−8

cm

∴ Number of revolution =

2×3.14×2.12×10

−8

1.09×10

8

=8.18×10

14

Hope this helped u

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