The number of roots of quadratic equation 8sec^2x - 6secx + 1 = 0 is
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Hi ,
8sec² x - 6secx + 1 = 0
8sec²x -4secx - 2secx +1 = 0
4secx ( 2secx - 1 ) - 1( 2secx - 1 ) = 0
( 2secx-1 )(4secx - 1 ) = 0
2secx - 1 = 0 or 4secx - 1 = 0
secx = 1/2 or sec x = 1/4
I hope this helps you.
:)
8sec² x - 6secx + 1 = 0
8sec²x -4secx - 2secx +1 = 0
4secx ( 2secx - 1 ) - 1( 2secx - 1 ) = 0
( 2secx-1 )(4secx - 1 ) = 0
2secx - 1 = 0 or 4secx - 1 = 0
secx = 1/2 or sec x = 1/4
I hope this helps you.
:)
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