The number of seats in each row of our school (ADIs) auditorium increases as you go back from the stage. The front row has 24 seats, the second row has 28 seats, and the third row has 32 seats If there are 52rows, find the seating capacity of the auditorium? (20 POINTS)
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Seats are to be arranged as 24 in the first row, 28
in the second row, 32 in the third row, and so on.
∴ Here,
a=24,
d=28-24 = 4
We have to find a
n
We know that,
a =a+(n−1)d
n
= 24 + (52-1)× 4
= 24+ 51×4
= 24 + 204
= 228
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