The number of shot in a triangular pile is greater by 150 than half the number of shot in a square pile, the number of layers in each being the same ; find the number of shot in the lowest layer of the triangular pile.
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This is an arithmetic sequence: 1,2,3,4... [counting down from the top of the pile]
The nth term of an arithmetic sequence is
a(n) = a(1) + (n-1)d where a(1) = the 1st term, d = the common difference
In this case a(n) = 1 + (n-1) = n
The sum of the 1st n terms of the sequence is S(n) = (n/2)(a(1) + a(n)) = 105
So S(n) = (n/2)(1+n) = 105
Solve for n:
n^2 + n - 210 = 0
Factor:
(n-14)(n+15) = 0
Take the positive solution, n=14
So there are 14 layers
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Sn = n/2 ( 2a (n-1) d ) = 150
n^2 + n - 210 = 0
(n -14) (n +15)
Therefore the correct answer is 14
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