Question

the number of sides of 2 regular polygons in the ratio 3:2 and their interior angles are in the ratio 5:3. Find the no. of their sides.

Answer 1

let sides of 1st polygon=3A,
sides of 2nd polygon=2A,

but now according to question, we have

[(3A-2)×180°/3A]/[(2A-2)×180°/2A] = 5/3,

[(3A-2)×2A]/[(2A-2)×3A] = 5/3,

(6A-4)/(6A-6) =5/3,

18A-12=30A-30,

30A-18A=-12+30,

12A=18,

A=3/2,

Answer 2

answer is the question 3/4