the number of sides of a regular polygon is given as q find the sum of the interior angles of each polygon
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We know that if a polygon has 'n' sides, then it is divided into (n – 2) triangles. We also know that, the sum of the angles of a triangle = 180°. Therefore, the sum of interior angles of a polygon having n sides is (2n – 4) right angles. Thus, each interior angle of the polygon = (2n – 4)/n right angles.
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