The number of sides of two regular polygons are in the ratio of 3:2 and their interior angles are in the ratio 5:3.Find the number of their sides.
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Answered by
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let sides of 1st polygon=3A,
sides of 2nd polygon=2A,
but now according to question, we have
[(3A-2)×180°/3A]/[(2A-2)×180°/2A] = 5/3,
[(3A-2)×2A]/[(2A-2)×3A] = 5/3,
(6A-4)/(6A-6) =5/3,
18A-12=30A-30,
30A-18A=-12+30,
12A=18,
A=3/2,
Check your question
sides of 2nd polygon=2A,
but now according to question, we have
[(3A-2)×180°/3A]/[(2A-2)×180°/2A] = 5/3,
[(3A-2)×2A]/[(2A-2)×3A] = 5/3,
(6A-4)/(6A-6) =5/3,
18A-12=30A-30,
30A-18A=-12+30,
12A=18,
A=3/2,
Check your question
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0
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