Question

The number of sigma and pi bonds present in a molecule of tetracyanoethylene (CN)2C =
C(CN)2 are
(1) 5 and 9
(2) 5 and 8
3) 9 and 9
(4) 9 and 7​

Answer 1

Answer:

hey here is ur answer

Explanation:

there r total 9 sigma and 9 pi in(CN) 2C

Answer 2

There are 9 ( nine ) sigma bonds and 9 ( nine ) pi bonds present in a molecule of tetracyanoethylene (CN)2C = C(CN)2 .

• Sigma bonds are stronger covalent bond then pie bond and they are formed due to head to head overlapping .

• Pie bonds are weaker in nature in compare to sigma bond . They are formed by lateral overlapping .