Question

The number of Silicon atoms per ${m}^{2}$ is 5 × ${10}^{28}$. This is doped simultaneously with 5 × ${10}^{22}$ atoms per ${m}^{3}$of Indium. Calculate the number of electrons and holes . Give that $\bf \: n_{i}$= 1.5 × ${10}^{16}$. ${m}^{-3}$.Is The material n- type or p - type?

Answer 1

$\huge\bold\red{Answer:-}$

Number of silicon atoms,

N=5×10^28atom/m^3

Number of arsenic atoms, n AS =5×10^22 atom/m^3

Number of indium atoms, n IN =5×10^22 atom/m^3

ni =1.5×10^16electron/m^3

ne =5×10^22 −1.5×10 ^6 =4.99×10 ^22

Let number of holes be nh

In thermal equilibrium, ne nh =n i^2

so, nh =4.51×10 ^9

ne >nH

, material is an n-type semiconductor.

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