Question

the number of six digit numbers that can be made with 0 1 2 3 4 5 so that even digit occupy odd places is​

Answer 1

Step-by-step explanation:

odd places are occupied by even numbers i.e., 0,2,4

There are 3 places so total =3! ways =6 ways

Now it should be a 6 digit number so the first digit can't be 0

So, we rule out 2 options

=6−2=4 ways

For the even places any of the 3 odd numbers can occupy in 3! ways =6 ways

Total =4.6 ways =24 ways