The number of solution(s) of the equation sgn(sin^(-1)x)= {2x} is (where {.} represents the fractional part function)
Answers
Answer:
Step-by-step explanation:
fractional part function and sgn(x) is dignum function) ... The number of solutions of the equation `tan^(-1)(4. play. 3:29 ... Consider the function f(x) = {x+2} [cos 2x ...
Answer:
The answer is 1
sgn{x} = Ι1 - x Ι
Step-by-step explanation:
Signum function is defined as :
sgn(x) = {-1 x < 0
0 x = 0
1 x > 0}
& 0 ≤ {x} < 1
- sgn{x} = 0 if {x} ∈ integer
- sgn{x} = 1 if x ∉ integer
- Ι x Ι = 0 if x ∈ integer
- Ι x Ι = 1 if x ∉ integer
for RHS = LHS
at x = 1 x → integer
∵these both cases are true only if x = 1
∴hence the answer is 1
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