The number of solutions for the equation sin 2x + cos 4x = 2 is
(a) 0
(b) 1
(c) 2
(d) ∞
Answers
Answered by
1
Solution:
Given,
sin 2x + cos 4x = 2
sin 2x + [1 – 2 sin2(2x)] – 2 = 0 {since cos 2A = 1 – 2sin2A}
sin 2x -1 – 2 sin2(2x) = 0
Let sin 2x = t
t – 1 – 2t2 = 0
2t2 – t + 1 = 0
Using the quadratic formula,
t = [1 ± √(1 – 8)]/2(2)
t = (1 ± √-7)/4
sin 2x = (1 ± i√7)/4
Therefore, there is no solution to x.
Answered by
1
Q) The number of solutions for the equation sin 2x + cos 4x = 2 is
(a) 0
(b) 1
(c) 2
(d) ∞
ANSWER:-
no solution the answer is be X .
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