Question

The number of solutions in a pair of linear equations given below is
x+2y- 8 = 0 and x + 4y = 16​

Answer 1

Given ,

A pair of linear equations are

• x + 2y = 8 and
• x + 4y = 16

Here ,

$\star \: \: \sf a_{1} = 1 \: , \: a_{2} = 1 \\ \\ \star \: \:\sf b_{1} = 2 \: , \: b_{2} = 4 \\ \\ \star \: \: \sf c_{1} = 8 \: , \: c_{2} = 16$

On comparing the ratios of $\sf \frac{ a_{1} }{a_{2} } \: , \: \frac{ b_{1} }{b_{2} }$ and $\sf \frac{ c_{1} }{c_{2} }$ , we get

$\sf \Rightarrow \frac{1}{1} ≠ \frac{2}{4}$

$\therefore \sf \underline{ \bold{The \: pair \: of \: linear \: equations \: \: has \: unique \: solution </p><p>}}$