The number of solutions of equation log(-2x)=2 log(x+1) is
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Answer:
(x+1) 2=-2x
x2+2x+1=-2x
x2+4x+1=0
no of solutions are 2
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2
Step-by-step explanation:
log(-2x)=2log(x+1)
log(-2x)=log(x+1)^2
-2x=(x+1)^2
-4x=x^2+1
as this a quadratic equation the no of solutions will be 2
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