Question

The number of solutions of the pair of equations x+2y-8=0 and 2x+4y=16 have *





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Answer 1

Step-by-step explanation:

First we have two eqns

x+2y-8=0..........eq 1

2x+4y=16...........eq2

....

By elimination method

multiple eq fjrst by 2 n multiple eq second by 1

the eqns will b

2x+4y-16=0

2x+4y-16=0

sub eq 2 by ist

we have

0=0

there will b two equal roots