Math, asked by selva1425, 10 months ago

the number of solutions, the equation 3x+5y+15=0 can have
1.one only
2.exactly two
3.no solution
4.infinite
explain​

Answers

Answered by akshi14
16

Answer:

infinite solutions we have for this equation

if x= 0

5y = -15

y = -3

if x = 1

you will get different y value

such a u can get infinite number of solutions

Answered by JeanaShupp
3

4) The given equation have infinite solution

Step-by-step explanation:

Given : linear equation in two variables 3x+5y+15=10

Now For finding the solutions

Let

x= 0

3\times 0 +5y=-15\\\\\Rightarrow 5y=-15\\\\\Rightarrow y =-3

Therefore (0,-3) is a solution

Now put x = 1 we get

3\times 1 +5y=-15\\\\\Rightarrow 5y=-15-3\\\\\Rightarrow 5y =-18\\\\\Rightarrow y =\dfrac{-18}{5}

Therefore (1,\dfrac{-18}{5} ) is also a solution

Continuing in this manner by putting the values of  x we will get the value of y . Therefore for each distinct value of x there exist a value of y

Hence, the given equation have infinite solution

#Learn more

Write any two solution of the equation 3x-y=10

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