The number of spherical nodes in an orbital of hydrogen-like species is
A) n − l B) n − l − 1 C) n + l − 1 D) n − l − 2
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Answer:(^_^)
Explanation:
S
1
state spherical symmetrical means l = 0,Number of nodal points = 1 (n - l - 1) = 1
(n - 0 - 1) = 1 ∴ n = 2
Hence 2s orbital corresponds to S
1
state
S
2
state has only one radial node and E = ground state of H atom
E
H
2
⊕
=
1
2
R
(for ground state)
E in S
1
state Li
2+
= -
1
2
R
(but this is equal -
n
2
Z
2
× R)
Since Z = 3 for Li
2+
ion
∴ n = 3
Since it has only one radial node:
(n - l - 1) = 1, ⇒ (3 - l - 1), ∴ l=1
Therefore, S
2
state corresponds to 3p (n=3,l=1)
E of S
2
state =
n
2
RZ
2
= R ×
2
2
3
2
=
4
9
R = 2.25 R
2.25 × E
H
2
⊕
in ground state
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