The number of students in a school increased from 2000 in the year 2010 to 2662 in the year 2013. Find the rate of increase.
Answers
Step-by-step explanation:
Let the total number of students of the school in the year 1998−1999 be x.
∴ Number of students in the year 1999−2000=x+20% of x=x+10020×x=x+5x=56x
Similarly no. of students in the year 2000−2001=56x+30% of56x=56x+10030×56x=5078x
∴ Effective increase in number of students=5078x−x=5028x
Thus, effective percentage increase=OriginalnumberofstudentsIncreaseinnumberofstudents×100=x5028x×100=56%
Let the total number of students of the school in the year 1998−1999 be x.
∴ Number of students in the year 1999−2000=x+20% of x=x+10020×x=x+5x=56x
Similarly no. of students in the year 2000−2001=56x+30% of56x=56x+10030×56x=5078x
∴ Effective increase in number of students=5078x−x=5028x
Thus, effective percentage increase=OriginalnumberofstudentsIncreaseinnumberofstudents×100=x5028x×100=56