Question

The number of students in each section of a school is 36.after admitting 12 new students new sectiona were started.if total number of students in each section now is 30,the number of sections initially were

Answer 1

Answer:

3

Step-by-step explanation:

let the no. of section before admitting 12 students be x

so , the no. of students = 36x

no. of sec after adding 12 students = x + 1

no. of students  = 30( x + 1)

according to question,

36x + 12 =  30(x+ 1)

⇒36x + 12 = 30x + 30

⇒36x - 30x = 30 - 12

⇒6x = 18

⇒x = 3

Answer 2

$\sf\huge\bold{Answer:}$

Given :

Initial number of students in each section = 36

After admitting 12 new students,

Final number of students in each section =30

To find :

Initial number of sections

Solution :

Let the no. of section before admitting 12 students = x

So,the initial no. of students = 36x

No. of students after 12 new admissions

$= initial \: no. + new \: admissions$

$= 36x + 12...(i)$

No. of sec after adding 12 students = x + 1

Final no. of students

$= students \: in \: 1 \:section \times total \: no.$

$= 30(x + 1)...(ii)$

$\fbox{ATQ(According to question)}$

Equating (i) and (ii)

:⟶36x + 12 =  30(x+ 1)

:⟶36x + 12 = 30x + 30

:⟶36x - 30x = 30 - 12

:⟶6x = 18

:⟶x = 3

$\: \therefore \\ ☆ \: \: initial \: no. \: of \: sections \: is \: 4 \: ☆$