The number of students in school A is 5 more than two times the number of students in school B. The product of the number of students in both the school is 81000. What is the number of students in school A?
Answers
Answered by
1
Step-by-step explanation:
let no of student in school A be X and school B be y given that-
x =2y+5. ---1
Xy = 81000. ---2
substitute 1 in 2--->
(2y+5)y = 81000
2y square + 5y=81000
2y^2 +5y -81000=0
further solve
Answered by
1
School B = x
School A = 5+2x
School A × School B = 81000
equation formed would be -
(5+2x) × (x) = 81000
2x^2 + 5x = 81000
2x^2 + x = 81000/5
2x^2 + x = 16200
x^2 + x = 16200/2
x^2 + x = 8100
x+x = √8100 (square root of 8100)
2x = 90
x = 90/2
x = 45
we need to find students in school A
School A = 5+2x
School A = 5 + 2×45
School A = 5+90
School A = 95
Hence there are 95 students in school A
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