Question

the number of terms common to the two AP's are 2+5+8+11+........+98 and 3+8+13+23+..........+198​

Answer 1

ANSWER

For first A.P

2+5+8+11+......+98

a = 2,an = 98, d = 3

an = a+(n−1)d

98 = 2+(n−1)3

98 = 2+3n−3

3n = 99

n = 33

Number of term =33

For first A.P

3+8+13+18+......+198

a = 3, an = 198, d = 5

an = a+(n−1)d

198 = 3+(n−1)5

198 = 3+5n−5

5n = 200

n = 40

No of terms = 40

Common terms = 40−33 = 7

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