Question

The number of terms in 2p² - 3pq + q² - 1 is ____________. *

Answer 1

Answer:

Given:(p

2

+q

2

+r

2

)(pq+qr)

Substituting p=2,q=−3 in the above equation, we get

=(2

2

+(−3)

2

+r

2

)(2×−3+(−3)r)

=(4+9+r

2

)(−6−3r)

=−(13+r

2

)(3r+6)

=−(39r+78+3r

3

+6r

2

)

=−(3r

3

+6r

2

+39r+78)