Question

The number of terms in 4p²q+3pq⁴-7 is ​

Answer 1

Step-by-step explanation:

Subtract 4p

2

q−3pq+5pq

2

−8p−7q−10 from 18−3p+11q+5pq−2pq

2

+5p

2

q

=18−3p+11q+5pq−2pq

2

+5p

2

q−(4p

2

q−3pq+5pq

2

−8p−7q−10)

=18−3p+11q+5pq−2pq

2

+5p

2

q−4p

2

q+3pq−5pq

2

+8p+7q+10

=28+5p+18q+8pq−7pq

2

+p

2

q