Question

)The number of terms in an A.P.4, -1, -6, …….. (-106) is ………….20. a) 23 b) 25 c) 20 d) 30​

Answer 1

Answer:

23

Step-by-step explanation:

First term (a)= 4

Nth term (t) = -106

Common difference = -1-(4) = -6-(-1) = -5

Formula for Nth term=>

t = a + (n-1)d

{Substitute the values}

=> -106 = 4 + (n-1)(-5)

=> -110 = (n-1)(-5)

=> 110/5 = (n-1)

=> 22 = n-1

=> n = 22+1 = 23

Therefore, the number of terms in the series is 23

Answer 2

Step-by-step explanation:

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Given,

The First Term [a] = 4

The N Term [t] = -106

Now,

Common Difference = -1-(4) = -6-(-1) = -5

Therefore,

Formula for N term =>

t = a + ( n - 1 ) d

Then,

{ Substituting the values }

=> -106 = 4 + ( n-1 ) ( -5 )

=> -110 = ( n-1 ) ( -5)

=> 110/5 = ( n-1 )

=> 22 = n-1

=> n = 22 + 1

=> 23

Since,

The no. of terms in the series is 23

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