Math, asked by bazila1, 3 months ago

The number of terms in the expansion of (2x + 3y − 5z)

8 is
(a) C(10, 8) (b) C(11, 8) (c) C(10, 3)​

Answers

Answered by pulakmath007
3

SOLUTION

TO CHOOSE THE CORRECT OPTION

The number of terms in the expansion of

 \sf{ {(2x + 3y - 5z)}^{8} } is

(a) C(10, 8)

(b) C(11, 8)

(c) C(10, 3)

EVALUATION

We know that the number of terms in the expansion of

 \sf{ {(x_1 +  x_2 + ... +  x_r)}^{n} } is

 \sf{ {}^{n + r - 1}C_{r - 1} }

Here the given expansion is

 \sf{ {(2x + 3y - 5z)}^{8} }

So r = 3 & n = 8

Hence the number of terms

 \sf{ =  {}^{8 + 3- 1}C_{3 - 1} }

 \sf{ =  {}^{10}C_{2} }

 \sf{ =  {}^{10}C_{10 - 2}  \:  \:  \bigg( \because \: \:{}^{n}C_{r}  = {}^{n}C_{n - r} \:  \bigg) }

 \sf{ =  {}^{10}C_{8}   }

 \sf{ =C(10,8) }

FINAL ANSWER

Hence the correct option is (a) C(10, 8)

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