The number of terms in the expansion of (x+a)^100+(x-a)^100
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3
Answer:
51
Step-by-step explanation:
( X + a ) ^ 100 = x*199 + nc1 ax^99 + nc2a^2x*98 + ....+nc99a^99x + a^100
( X - a ) ^ 100 = x*199 - nc1 ax^99 + nc2a^2x*98- .... - nc99a^99x + a^100
50 terms will cancel each other
and
51 terms will add up to each other
the result will be 51 terms
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