Math, asked by shahmaa644, 1 month ago

the number of terms in the expansion (x+a)^9=​

Answers

Answered by prithikashree235
0

Step-by-step explanation:

(x+a)

47

−(x−a)

47

When we expand the above equation using binomial expansion

(x+y)

n

=(

k=0

n

n

C

k

x

k

y

n−k

)

So the above equation becomes

(x+a)

47

=(

k=0

47

47

C

k

x

k

a

47−k

)

(x−a)

47

=(

k=0

47

47

C

k

x

k

(−a)

47−k

)

(x+a)

47

⇒There are 48 terms in the expansion and all are positive

(x−a)

47

⇒There are 48 terms in the expansion

The terms with odd powers of a will be cancelled and those with even powers of a will add up.

24 terms will be positive and 24 negative in the expansion of (x−a)

47

48 terms positive-[24 terms negative and 24 terms positive]

=48termspositive+24termsnegative+24termspositive

=24 terms

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Answered by RhonnyGaming
0

Answer:

(x+a)

47

−(x−a)

47

When we expand the above equation using binomial expansion

(x+y)

n

=(

k=0

n

n

C

k

x

k

y

n−k

)

So the above equation becomes

(x+a)

47

=(

k=0

47

47

C

k

x

k

a

47−k

)

(x−a)

47

=(

k=0

47

47

C

k

x

k

(−a)

47−k

)

(x+a)

47

⇒There are 48 terms in the expansion and all are positive

(x−a)

47

⇒There are 48 terms in the expansion

The terms with odd powers of a will be cancelled and those with even powers of a will add up.

24 terms will be positive and 24 negative in the expansion of (x−a)

47

48 terms positive-[24 terms negative and 24 terms positive]

=48termspositive+24termsnegative+24termspositive

=24 terms

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