Question

the number of terms in the series 101,99,97,...........,47 is​

Answer 1

The number of terms in the series 101 + 99 + 97 + ... + 47 is

(1) 25

(2) 28

(3) 30

(4) 20

Solution:

Here a = 101

Common difference, d = 99-101 = -2

an = a+(n-1)d = 47

101+(n-1)-2 = 47

101 -2n + 2 = 47

2n = 56

n = 56/2 = 28

Hence option (2) is the answer.

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