the number of terms of an AP 3,5,7_____must be taken so that the sum 120 are____
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Answered by
0
Answer:
Step-by-step explanation:
10
Answer. thus there are 10 terms of the given AP must be added to get sum 120.
Answered by
0
Answer:
Let's see .
3,5,7,9,11_ _ _
so the first no is considered as First term as (a) and the difference between 2nd and 1st term is taken as common difference i.e d
so, a=3 and d=5-3=2
according to the formula Sn=n/2(2a+(n-1)d)
120=n/2(6+(n-1)2)
120×2=n(6+2n-2)
240=n(2n+4)
240=2n²+4n
2n²+4n-240=0
n²+2n-120=0
n²+12n-10n-120=0
n(n+12)-10(n+12)=0
n=10
the number of terms will be 10-4=6 terms
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