Question

The number of terms of an AP 5, 9, 13, .... 185 is
(a)31 (b)51 (c)41 (d)40​

Answer 1

Answer:

46

Step-by-step explanation:

NOTE :

• Tn = a + ( n - 1 ) d
• a = 1st term = 5
• d = common difference = 2nd term - 1st term = 9 - 5 = 4
• Tn = nth term = 185

Tn = a + ( n - 1 ) d

=> 185 = 5 + ( n - 1 ) 4

=> 185 = 5 + 4n - 4

=> 185 = 1 + 4n

=> 185 - 1 = 4n

=> 4n = 184

=> n = 184 / 4

=> n = 46