Math, asked by harshitkangokar919, 5 hours ago

The number of terms of the A.P. 26, 22, 18, 14, ... that must be taken for the sum to be - 64 is

Answers

Answered by shireensher178
3

Answer:

n=2

Step-by-step explanation:

-64=n/2[2a+(n-1)d]

-64=n/2[52+(n-1)-4]

-128=n[56-4n]

-32=n[14-n]

-32=14n-n^2

n^2-14n-32=0

n^2-2n+16n-32=0

n=-16,n=2

no. of terms will be +ve thus n=2

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Answered by amitnrw
2

Given : A.P. 26, 22, 18, 14, ...  

To Find : The number of terms of the A.P.  must be taken for the sum to be - 64  

Solution:

Arithmetic sequence : Sequence of terms in which difference between one term and the next is a constant.

This is also called Arithmetic Progression AP

Arithmetic sequence can be represented in the form :

a, a + d  , a + 2d , …………………………, a + (n-1)d

a = First term

d = common difference = aₙ-aₙ₋₁

nth term =  aₙ =  a + (n-1)d  

Sₙ = (n/2)(2a + (n - 1)d)

Sum of Arithmetic sequence (AP) is called Arithmetic series

26, 22, 18, 14, ...  

a = 26

d = - 4   ( 22 - 26 = - 4   = 18 - 22)

Terms = n

Sₙ = -64

Sₙ = (n/2)(2a + (n - 1)d)

=> -64 = ( n/2)(2 * 26 + (n - 1)(-4))

=> -64 = n ( 26  - 2n  + 2)

=> --64 = n ( 28 - 2n)

=> -32 = n ( 14 - n)

=> -32 = 14n - n²

=> n² - 14n - 32 = 0

=> n² - 16n + 2n - 32 = 0

=> n (n - 16) + 2(n  - 16) = 0

=> (n - 16)(n + 2) = 0

=> n = 16 , n = -2

Terms can not ne negative

n = 16

16 terms must be taken for the sum to be -64

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