Question

the number of the boys and girls in a class are in the ratio of 7:5. the number of the boys is 8 more than the number of girls find the strength of the class​

Answer 1

Given :

• The number of the boys and girls in a class are in the ratio of 7:5.
• The number of the boys is 8 more than the number of girls.

To find :

• The strength of the class =?

Step-by-step explanation :

Let, the number of girls be, 5x.

Then, the number of boys be, 7x.

It is Given that,

The number of the boys is 8 more than the number of girls.

As per question,

5x + 8 = 7x

7x - 5x = 8

2x = 8

x = 8/2

x = 4

Therefore, We got the value of, x = 4.

Hence,

Number of girls, 5x = 5 × 4 = 20

Number of boys, 7x = 7 × 4 = 28.

Thus, the total strength of the class is 20+28=48

Answer 2

GIVEN :-

•The number of the boys and girls in a class are in the ratio of 7:5.

•The number of the boys is 8 more than the number of girls .

TO FIND :-

• The strength of the class.

SOLUTION :-

•Let,

=> The number of boys in class be 7R.

=> And the number of girls in class be 5R.

•The number of the boys is 8 more than the number of girls .

=> 5R + 8 = 7R

=> 7R - 5R = 8

=> 2R = 8

=> R = 4 .

Hence,

=> Number of boys = 7R= 7 × 4 = 28 .

=> Number of girls = 5R = 5 × 4 = 20 .

=>The strength of the class = Number of boys + Number of girls .

=> The strength of the class = 28 + 20

=> The strength of the class = 48 .

Therefore, the total strength of the class is 48 .