The number of three english letter words having at least one consonant but not having two consecutive consonants
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These are the 4 possible types of words we can make and the number of words we can make are:
VCV = 5 x 21 x 5 = 525
CVV = 21 x 5 x 5 = 525
VVC = 5 x 5 x 21 = 525
CVC = 21 x 5 x 21 = 2205
Total words : 525 + 525 + 525 + 2205 = 3780
Please note: We have calculated words on condition of repetition.
VCV = 5 x 21 x 5 = 525
CVV = 21 x 5 x 5 = 525
VVC = 5 x 5 x 21 = 525
CVC = 21 x 5 x 21 = 2205
Total words : 525 + 525 + 525 + 2205 = 3780
Please note: We have calculated words on condition of repetition.
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