The number of turns in a long solenoid is 500. The area of cross-section of solenoid is 2 10-3 m2. If the value of magnetic induction, on passing a current of 2 amp, through it is 5 10-3 tesla, the magnitude of magnetic flux connected with it in webers will be
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Answer:
5×10^-3
Explanation:
Magnetic flux of toroid having n number of turns is
= nBA
B -> magnetic induction
A-> area of cross section
= 500 × 2 × 10^(-3) × 5 × 10^(-3)
= 10³ × 10^(-3) × 5 × 10^(-3)
= 5 × 10^(-3)
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