Question

the number of turns per unit length of a long solenoid is 10. if it's average radius is 5 cm and it carries a current of 10A, then the ratio of fluxes densities at the centre and at the end on the axis will be​

Answer 1

Answer:

2.

Explanation:

The magnetic field at the center of the solenoid will be μ₀ni((sin90+sin90)/2) which will be μ₀ni. Since, the angles will be 90 and 90 for the center of the magnetic field.

The magnetic field at the ends will be μ₀ni((sin90+sin0)/2) since the two angle of the end is 90 and 0 degree so the magnetic field will be μ₀ni/2.

Therefore, the ratio will be magnetic field at the center / magnetic field at the end.

μ₀ni/μ₀ni/2 = 2.