the number of turns per unit length of a long solenoid is 10. if it's average radius is 5 cm and it carries a current of 10A, then the ratio of fluxes densities at the centre and at the end on the axis will be
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Answer:
2.
Explanation:
The magnetic field at the center of the solenoid will be μ₀ni((sin90+sin90)/2) which will be μ₀ni. Since, the angles will be 90 and 90 for the center of the magnetic field.
The magnetic field at the ends will be μ₀ni((sin90+sin0)/2) since the two angle of the end is 90 and 0 degree so the magnetic field will be μ₀ni/2.
Therefore, the ratio will be magnetic field at the center / magnetic field at the end.
μ₀ni/μ₀ni/2 = 2.
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