Question

The number of two digit combinations
having 9 as atleast one of the digits from
the digit 0,6,9,5, 4 is :​

Answer 1

The number of two digit combinations = 10

Step-by-step explanation:

• We are given 0, 6, 9, 5, 4 five numbers. But, each two digit number has at least 9. So, only one place is empty.

• Here,  we can choose in $^5C_1$ways to fill one place in two digit number. The second place is filled by 9 always.

Both these digits can be arranged in$2!$ ways.

Thus, the required number of ways = $^5C_1\times2!$ = 10

Answer 2

Answer:

10.

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