Question

the number of two digit numbers of the form aa with same digits having exactly four divisors is​

Answer 1

Answer:

Step-by-step explanation: The only possible outcomes of two digit numbers in the form aa can be 11,22,33,44,55,66,77,88,99

the formula for finding the number of divisors is taking the powers of a numbers prime factors and multiplying both of them after adding +1 to each. Therefore only

22 = 2 x 11 = 2 to the power 1+1 =2

11 to the power 1 +1= 2

2 into 2 = 4 divisors.

Hence the numbers which satisfy this property are - 22 33 55 and 77

Therefore the answer is 04.

Answer 2

Concept Introduction:-

It may be in the form of a word, a symbol, or a figure that reflects the arithmetic value of a quantity.

Given Information:-

We have been given that the number of two digit numbers of the form aa with same digits having exactly four divisors.

To Find:-

We have to find that the number of two digit numbers of the form aa with same digits having exactly four divisors is

Solution:-

According to the problem

The only possible outcomes of two digit numbers in the form aa can be $11,22,33,44,55,66,77,88,99$.

The formula for finding the number of divisors is taking the powers of a numbers prime factors and multiplying both of them after adding $+1$ to each. Therefore only

$22 = 2 \times 11 = 2$ to the power $1+1 =2$

$11$ to the power $1 +1= 2$

$2$ into $2 = 4$ divisors.

Hence the numbers which satisfy this property are - $22$ $33$ $55$ and $77$.

Final Answer:-

The correct answer is $4$.

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