Question

the number of unit cells in 936 AMU of sodium chloride is ​

Answer 1

Answer:

The number of unit cells in 936 AMU of sodium chloride is 4 UNIT CELLS

Explanation:

• NaCl crystallizes in fcc structure.
• A fcc structure contains 4 atoms/ions/molecules per unit cell.
• Molecular mass of Sodium(Na)= 23gmol⁻¹
• Molar mass of Chlorine(Cl) = 35.5gmol⁻¹
• Molecular mass of Sodium chlorine (NaCl)=58.5gmol⁻¹
• One unit cell of NaCl contains 4 formula units

Mass of one unit cell = 4(Molecular mass of Na+ Molecular mass of Cl)

                                   $\\ =4(23+35.5) \\= 58.5 × 4 amu \\=234amu$

No. of unit cell in 936 amu = $\frac{936}{(58.5*4)} =4 amu$

Answer 2

Answer:

No .of unit cells =4 unit cells .  

Explanation:

TO FIND: The number of unit cells in 936 AMU of sodium chloride is ​

GIVEN:

      936 Atomic mass unit  

     Sodium chloride crystalizes in a face centered cubic structure which has 4 formula units of molecules.

Number of atoms in 1 unit cell of sodium chloride is $4Na^{+} +4Cl^{-}$

                      Atomic mass of sodium chloride is $4* mass of NaCl$

              Atomic mass of Na is 23

             Atomic mass of Cl is 35.5

                                                                           =$4*(23+35.5)$

                                                                                  $4*58.5\\=234$   amu

           No of unit cells =$\frac{934 amu}{234 amu}$

            No .of unit cells =4 unit cells .  

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