Math, asked by GSSSGFGH1020, 11 months ago

The number of values of a for which (a^2-3a+2)x^2+(a^2-5a+6)x+a^2-4=0 is an identity in x is

Answers

Answered by brunoconti
11

Answer:

Step-by-step explanation:

BRAINLIEST BRAINLIEST BRAINLIEST

Attachments:
Answered by pavit15
2

Answer:

1

Step-by-step explanation:

For the given equation to be an identity in ‘x’, the equation must be satisfied for all x.

One way is: Putting x = 0, and x = 1, we can narrow down the value as a = 2

OR : (a-2) is a common factor of the terms, so if a = 2, the equation becomes an identity in x.

Similar questions