The number of values of a for which (a^2-3a+2)x^2+(a^2-5a+6)x+a^2-4=0 is an identity in x is
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Step-by-step explanation:
For the given equation to be an identity in ‘x’, the equation must be satisfied for all x.
One way is: Putting x = 0, and x = 1, we can narrow down the value as a = 2
OR : (a-2) is a common factor of the terms, so if a = 2, the equation becomes an identity in x.
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