Question

the number of values of x and y that satisfy the equation x²+y²=2007​

Answer 1

not sure but its impossible

Answer 2

Answer:

No such integers exist.

Step-by-step explanation:

Here, x^2+y^2=2007

Now we can write one perfect square number at this form (8m+1) ,where m is a some positive integers

So now x^2+y^2=2007

(8m+1)+(8n+1)=2007 ( m, n are possitive integers)

8(m+n)=2005

Since here left hand side is even but right hand side is odd. So its not possible.

So there is no any possible possitive integer which satisfaid the equation x^2+y^2=2007

Hope it helps..!!