Question

The number of water molecules present in a drop of water weighing 0.05 mg

a) 1.666×10¹⁶
b)16.66×10¹⁸
c)1.666×10¹⁷
d)12.046×10²²​

Answer 1

Answer:

here is the answer

Explanation:

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Answer 2

Answer:

1.637x10^(18) molecules

Explanation:

No of water molecules present in 18 gram of water is equal to Avagardo number

which is 6.023x10^23.

0.05 mg = 5x10^(-2) mg = 5x10^(-5) g

To find the number of molecules

= [5x10^(-5)/18] x 6.023x10^23

= (5/18) x 6.023 x 10^(18)

= 1.673 x 10^18

I am sorry if something is wrong but I think I am correct and I checked the calculations many times I am telling thus because there us no option for the answer I got.