Question

the number of waves made by a bohr electron in an orbit of maximum magnetic quantum number +2 is

Answer 1

maximum quantum number m =+2

since m can take the values from -l to +l,for n to be maximum l should be +2

Further l can take values form 0 to n-1

for maximum n,

l=n-1

2=n-1

n=3

Answer 2

Answer: The number of waves made by Bohr electron in an orbit will be 3.

Explanation:

Number of waves is equal to the principle quantum number.

Principle Quantum Numbers: It describes the size of the orbital and the energy level. It is represented by n. Where, n = 1,2,3,4....

Azimuthal Quantum Number: It describes the shape of the orbital. It is represented as 'l'. The value of l ranges from 0 to (n-1). For l = 0,1,2,3... the orbitals are s, p, d, f...

Magnetic Quantum Number: It describes the orientation of the orbitals. It is represented as $m_l$. The value of this quantum number ranges from $(-l\text{ to }+l)$. When l = 2, the value of $m_l$ will be -2, -1, 0, +1, +2.

We are given:

$m_l=+2$

From this, we can easily tell, l = 2 because $m_l=+l\text{ to }=l$

And also,

n = 3  because  l = n-1

Hence, the number of waves made by Bohr electron in an orbit will be 3.