Math, asked by hirthickkumaran7873, 11 months ago

The number of ways in which 6 different marbles can be put in two boxes of different sizes so that no box remains empty

Answers

Answered by bunny7970
0

Step-by-step explanation:

The number of ways in which 6 different marbles can be put in two boxes of different sizes Are

6*6=36

Answered by FelisFelis
3

There are 62 ways in which 6 different marbles can be put in two boxes so that no box remains empty.

Step-by-step explanation:

Consider the provided information.

We have 6 different marbles which can be put in two boxes.

For each marbles we have two boxes so total number of ways are:

2\times2\times2\times2\times2\times2=2^6

But it is given that no box remains empty. There are only 2 ways in which all the marbles can be put either in the first box or in the second box.

Thus, the number of ways in which 6 different marbles can be put in two boxes of different sizes so that no box remains empty is:

2^{6}-2=64-2=62

Hence, there are 62 ways in which 6 different marbles can be put in two boxes so that no box remains empty.

#Learn more

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