the number of ways in which 6 men can be arranged in a row so that the particular 3 men sit together, is
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Given:
Total number of people = 6
To find:
The probability that particular three men always sit together.
Solution:
The total possibility of arranging 6 people = 6!
Let's assume the group of three people as a single person, then the total number of people will be 4.
Total possibility to arrange these 4 people = 4!
We can arrange these 3 people within themselves, therefore the probability becomes 4!3!
The required probability = 4! 3! / 6!
= 1/5
Therefore, the required probability is 1/5.
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