the number of ways in which 6boys and 7girls can sit in a row such that 1] no two girls are together is 2] no two boys are together 3] they sit alternately
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1)6!×7!
2)7!×8p5
3)6!×7!
hope these are the answers
2)7!×8p5
3)6!×7!
hope these are the answers
nallanagulasaip:
in detail
Answered by
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Hey there !!!
1) No two girls sit together
So there are 6 boys and 7 girls so first arranging the boys
_B_B_B_B_B_B_ now we have arranged boys in 6 places and between boys there are 7 empty places in which girls can be arranged.
So number of ways for this arrangement is
= 7!*6!
2)No two boys are together
So first we need to arrange girls
_G_G_G_G_G_G_G_ so between 7 girls there are 8 vacant places for 6 boys so arrangement will be =8C6*7!
3)They sit alternatively
G B G B G B G B G B G B G =6!*7!
Hope this helped you !!
1) No two girls sit together
So there are 6 boys and 7 girls so first arranging the boys
_B_B_B_B_B_B_ now we have arranged boys in 6 places and between boys there are 7 empty places in which girls can be arranged.
So number of ways for this arrangement is
= 7!*6!
2)No two boys are together
So first we need to arrange girls
_G_G_G_G_G_G_G_ so between 7 girls there are 8 vacant places for 6 boys so arrangement will be =8C6*7!
3)They sit alternatively
G B G B G B G B G B G B G =6!*7!
Hope this helped you !!
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