Math, asked by nallanagulasaip, 1 year ago

the number of ways in which 6boys and 7girls can sit in a row such that 1] no two girls are together is 2] no two boys are together 3] they sit alternately

Answers

Answered by Kartik09
1
1)6!×7!
2)7!×8p5
3)6!×7!
hope these are the answers

nallanagulasaip: in detail
nallanagulasaip: plzzz
Kartik09: no two girls sits together so we need to arrange the boys first _B_B_B_B_B_B_ ,,boys can be arranged in 6! ways and for gilrls there are 7 places so the can be arranged in 7! ways
Kartik09: 2)when no two boys are together then at corst arrange girs _G_G_G_G_G_G_G_ ,,girls can be arrnged in 7! ways and we have 8 places for 5 boys so they can be arranged in 8p5 ways (7!×8p5)
Kartik09: 3)when they dit alternately i.e GBGBGBGBGBGBG they can be arranged in 6!×7! ways
Answered by pankaj12je
7
Hey there !!!

1) No two girls sit together

So there are 6 boys and 7 girls so first arranging the boys

_B_B_B_B_B_B_  now we have arranged boys in 6 places and between boys there are 7 empty places in which girls can be arranged.
So number of ways for this arrangement is
                        = 7!*6!

2)No two boys are together
So first we need to arrange girls
_G_G_G_G_G_G_G_ so between 7 girls there are 8 vacant places for 6 boys so arrangement will be =8C6*7!

3)They sit alternatively 
G B G B G B G B G B G B G  =6!*7!

Hope this helped you !!
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